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1 point
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I never said this. What are you talking about?

The gradient of any line is mx + c = y, that’s grade school math. That’s all you used to work it out and you’re claiming you used calculus.

Alas, the answer for the coveted star was:

Multiply the equation with d/dt: (d/dt) * t*sqrt(26) = dt * sqrt(26) / dt.

dts cancel out, therefore the derivative is sqrt(26).

Still a very unnecessary (and simple) application of calculus, but at least it would’ve shown that’s whatcha did.

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4 points

I never used the slope equation. I took a derivative d/dt. I clearly indicated the step where I did that. At this point, I can only conclude that you’re keeping this going out of some weird desire to get one over on me, so I’m gonna disengage.

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