we can simplify this by measuring the boy-girl triplet spin state, obviously
Oh no I didn’t account for the fact that ppl existing in a gender superposition don’t necessarily exist in a real valued vector space
I wanna touch grass, but with this commenter together
<3
And the moral of the story? Betting and gambling is haram.
this implies gender does not have a z axis
Actually it doesn’t, it merely projects all genders onto the male/female plane. I don’t think this is incorrect for this purpose, for instance if we consider a xenogender entirely orthogonal to the two standard basis vectors, projection onto the male/female plane yields coordinates of (0,0). It would be reductive to say that this is equivalent to other genders that map to this point, however, it still correctly yields the result of a tie. This is the natural outcome of neither player betting on a xenogender
“greater than" and “less than” are missing the “or equal to”. A difference of exactly 1 should be sufficient for an absolute victory. I’m also missing a definition of what negative numbers on an axis mean, since they are currently implied to reach absolute victories and are not excluded by the definition. I’ll show myself out 😅
We simply define the two dimensional space as an empirical observation, where the median man is located at position (0,1). So there potentially exist men at position (0.1,1.1) but the epicenter of masculinity is at this coordinate - similarly so for female. In the construction of this simplified geometric space we have no guarantees except the median property of the two most popular genders. Since nonbinary genders frequently defy notions of categorization there is no reason to believe that the projection of an extremely high dimensional gender into this space will yield numbers with any meaningful properties. All we can say for certain is that a Manhattan distance greater than or equal to one is sufficient for an absolute win.
